Infinitive or –ing put the verb in brackets in the right form, infinitive (with or without to), or –ing. sometimes two forms are possible. model: i enjoy walking (walk) in the rain. would you like to have (have) something to eat? it started to rain / raining (rain) while we were out. a) my family is trying (decide) where to go on holiday. b) i’d like (go) somewhere different for a change. c) i enjoy (visit) places i’ve never been to before. d) but my children hate (sightsee). e) they prefer (play) in a swimming pool all day. f) they refuse (go) out on trips if it’s too hot. g) a lady from travel agency helped us (choose) a nice house. h) when we arrived, the people next door invited us (have) a drink with them. i) we began (talk) about next year’s holiday two months ago. j) everyone hopes (enjoy) themselves on holiday, but it isn’t always easy. k) my wife and i are starting (think) we should stay at home.

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Daina1115

Английский язык

4,5(28 оценок)

A) my family is trying to decide where to go on holiday. b) i’d like to go somewhere different for a change. c) i enjoy visiting places i’ve never been to before. d) but my children hate sightseeing. e) they prefer playing in a swimming pool all day. f) they refuse to go out on trips if it’s too hot. g) a lady from travel agency helped us to choose a nice house. h) when we arrived, the people next door invited us to have a drink with them. i) we began to talk about next year’s holiday two months ago. j) everyone hopes to enjoy themselves on holiday, but it isn’t always easy. k) my wife and i are starting to think we should stay at home.

talanovaelena2

Английский язык

4,8(57 оценок)

105

Объяснение:

Необходимо найти угол АСВ. Обозначим центр точкой О. Построим центральный угол АОВ, так же построим вписанный угол ADB.Для начала определим угловые меры дуг АСВ и ADB. Сказано, что хорда AB делит окружность на две части, градусные величины которых относятся как 5:7. Введём коэффициент пропорциональности х, получим: 5х+7х=360

12х=360

х=30

Значит хорда АВ делит окружность на две части градусные величины которых равны:

дуга асв 5 *30=150

дуга адв 7*30=210

Воспользуемся свойством вписанного угла. Известно, что он равен половине центрального угла, опирающегося на ту же дугу. В данном случае

угол адв =0.5*150=75

Рассмотрим четырёхугольник ADBC. Известно, что сумма противоположных углов четырёхугольника вписанного в окружность равна 1800, значит

угол асв=185-75=105

ответ: 105