Ответы на вопрос:
(cos 7x -cos3x) +(sin8x+sin2x) =0; - 2sin2xsin5x +2sin5xcos3x = 0; sin5x(sin2x -cos3x) =0 ; sin5x=0 ⇒ x =π*k/5 ,k ∈z . sin2x -cos3x =0 sin2x -sin(π/2 -3x) =0; 2sin(5x/2 -π/4)*cos(π/4 -x/2) =0 ; sin(5x/2 -π/4)*cos(x/2 -π/4 ) =0 ; sin(5x/2 -π/4) =0⇒5x/2 -π/4 =π*k ⇔ x = π/10+2π/5*k,k ∈z cos(x/2 -π/4)= 0 ⇒x/2 - π/4 =π/2 +π*k ⇔ x=3π/2+2π*k ,k∈z *********************************************************************** sin2x -cos3x=0; 2sinxcosx -cosx(4cos²x -3) =0; ² cosx(2sinx -4cos²x +3) =0 cosx(4sin²x +2sinx -1) =0
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