Ответы на вопрос:
Замена переменной: t=x² t²=x⁴ t²-3t+2≤0 t²-3t+2=0 d=(-3)²-4*2=9-8=1 t₁=(3-1)/2=1 t₂=(3+1)/2=2 + - + 1 2 \\\\\\\\\\\\\\\\\ t∈[1; 2] 1≤t≤2 1≤x²≤2 {x²≥1 {x²≤2 x²≥1 x²-1²≥0 (x-1)(x+1)≥0 x=1 x= -1 + - + - -1 1 \\\\\\\\\\\\\ \\\\\\\\\\\\\\\ x∈(-∞; -1]u[1; +∞) x²≤2 x²-(√2)²≤0 (x²-√2)(x²+√2)≤0 x=√2 x= -√2 + - + -√2 √2 \\\\\\\\\\\\\\ x∈[-√2; √2] {x∈(-∞; -1]u[1; +∞) {x∈[-√2; √2] ⇒ x∈[-√2; -1]u[1; √2] ответ: [-√2; -1]u[1; √2].
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