Ответы на вопрос:
5y - x = 4 x^2 + 3y^2 = 4 •••••• x = 5y - 4 ( 5y - 4 )^2 + 3y^2 = 4 25y^2 - 40y + 16 + 3y^2 - 4 = 0 28y^2 - 40y + 12 = 0 4( 7y^2 - 10y + 3 ) = 0 d = 100 - 84 = 16 = 4^2 y1 = ( 10 + 4 ) : 14 = 1 y2 = ( 10 - 6 ) : 14 = 2/7 x = 5y - 4 x1 = 5•1 - 4 = 1 x2 = 5•( 2/7 ) - 4 = ( 10/7 ) - 4 = 1 3/7 - 3 7/7 = - 2 4/7 ответ ( 1 ; 1 ) ; ( - 2 4/7 ; 2/7 )
=21(12+14)+26*79=21*26+26*79=26(21+79)=26*100=2600 =4,3*2,8-2,8*3,1-3,8*1,2=2,8(4,3-3,1)-3,8*1,2=2,8*1,2-3,8*1,2=1,2(2,8-3,8)= =1,2*(-1)=-1,2
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