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Решите уравнение: х/22,5=13/15; 2,2/31 =110/у

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X/22,5=13/15 15x=292,5 x=19,5 2,2/31=110/x 2,2x=3410 x=1550

1) \frac{3}{7} + \frac{5}{6} = \frac{18}{42} + \frac{35}{42} = \frac{53}{45} = 1 \frac{8}{45}

2) \frac{5}{14} \times \frac{7}{30} = \frac{1}{12}

 \frac{11}{12} - \frac{7}{8} = \frac{22}{24} - \frac{21}{24} = \frac{1}{24}

[tex]1
\frac{8}{25} \times 1 \frac{4}{11} = \frac{33}{25} \times \frac{15}{11} = \frac{9}{5} = 1 \frac{4}{5} = \\ = 1.8[/tex]

 \frac{5}{9} \div \frac{10}{27} = \frac{5}{9} \times \frac{27}{10} = \frac{3}{2} = 1 \frac{1}{2} = 1.5

[tex]4 \frac{4}{9} \div 1 \frac{2}{3} = \frac{40}{9}
\times \frac{3}{5} = \frac{8}{3} = 2 \frac{2}{3} [/tex]

14 - (6 \frac{8}{16} + 3 \frac{4}{16} ) = 14 - 9 \frac{12}{16} = \\ = 13 \frac{16}{16} - 9 \frac{12}{16} = 4 \frac{4}{16} = 4 \frac{1}{4}

[tex]7 \frac{1}{3} \times ( \frac{9}{20} \div \frac{1}{30} ) = 7 \frac{1}{3}
\times \\ ( \frac{9}{20} \times \frac{30}{1} ) = 7 \frac{1}{3} \times \frac{27}{2} = [/tex]

 \frac{22}{3} \times \frac{27}{2} = 99

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