Надо найти массовую долю crn(o3)3, baco3, ag2co3, mgio3,napo3 (20 ) heeeeeelp
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Ответы на вопрос:
Cr(no3)3 m(cr(no3)3)=52+(14+16*3)*3=238g/mol w(cr)=52/238*100%=21.85% w(n)=14*3/238*100%=17.65% w(o)=16*9/238*100%=60.5% baco3 m(baco3)=137+12+16*3=197g/mol w(ba)=137/197*100%=69.54% w(c)=12/197*100%=6.09% w(o)=16*3/197*100%=24.37% ag2co3 m(ag2co3)=108*2+12+16*3=276g/mol w(ag)=108*2/276*100%=76.26% w(c)=12/276*100%=4.35% w(o)=16*3/276*100%=17.39% mgio3 m(mgio3)=24+127+16*3=199g/mol w(mg)=24/199*100%=12.06% w(i)=127/199*100%=63.82% w(o)=16*3/199*100%=24.12% napo3 m(napo3)=23+31+16*3=102g/mol w(na)=23/102*100%=22.55% w(p)=31/102*100%=30.39% w(o)=16*3/102*100%=47.06%
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