Ответы на вопрос:
в) 3х^2+х-4> 0
3x^2+x-4=0
d=1^2-4*3*(-4)=1+48=49 v49=7
x1=-1+7/6=1
x2=-1-7/6=-8/6=-4/3
г) 2х^2-х-1≤0
2x^2-x-1=0
d=(-1)^2-4*2*(-1)=1+8=9 v9=3
x1=1+3/4=1
x2=1-3/4=-2/4=-1/2
е) 16х2-25≥0
(4x-5)(4x+5)> =0
4x-5*4x+5> =0
4x+4x> =5-5
x> =8
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