Ответы на вопрос:
Sinx+cosx=sinx+sinx(π/2-x)=2sinπ/4cos(x-π/4)=√2cos(x-π/4) √2|cos(x-π/4)\< √2/2 |cos(x-π/4)|< 1/2 -1/2< cos(x-π/4)< 1/2 π/3+2πn< x-π/4< 2π/3+2πn u 4π/3+2πn< x-π/4< 5π/3+2πn 7π/12+2πn< x< 11π/12+2πn u 19π/12+2πn< 23π/12+2πn,n∈z
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