Ответы на вопрос:
F(x)=x2−9x+1−−−−−−√решение. способ 1 f′(x)=(x2−9x+1−−−−−−√)′= =(x2−9x+1)′2⋅x2−9x+1−−−−√= =(x2−9)′⋅(x+1)−(x2−9)⋅(x+1)′(x+1)22⋅x2−9x+1−−−−√= =(x2)′⋅(x+1)−(x2−9)⋅1(x+1)22⋅x2−9x+1−−−−√= =2⋅x⋅(x+1)−(x2−9)(x+1)22⋅x2−9x+1−−−−√ответ: 2⋅x⋅(x+1)−(x2−9)(x+1)22⋅x2−9x+√x^2-9)/(x+1
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