Ответы на вопрос:
3*7 div 2 mod 7/3 - trunc(sin(1)) = 21 div 2 mod 7/3 - trunc(sin(1)) = 10 mod 7/3 - trunc(sin(1)) = 3/3 - trunc(0.8) = 1.0 - 0 = 1.0
А= 10 b = 20b = а + b = 10 +20 = 30a = 10 b = 30a = b - а = 30 - 10 = 20a = 20 b = 30b = b + а = 30 + 20 = 50a = 20 b = 50 a = 20 b = 50
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