Ответы на вопрос:
Решение а) (x+3) (x-4) = -12 x² - x - 12 = - 12 x² - x = 0 x(x - 1) = 0 x₁ = 0 x - 1 = 0 x₂ = 1 б) 1 2/3 t + (2t + 1) (1/3 t - 1 ) = 0 5/3 t + (2/3)*t² - 2t + (1/3)t - 1 = 0 (2/3)*t² - 1 = 0 2t² - 3 = 0 t² = 3/2 t₁ = - √(3/2) t₁ = - √6/2 t₂ = √6/2 в) 3x (2x + 3) = 2x (x + 4, 5) + 2 6x² + 9x = 2x² + 9x + 2 4x² = 2 x² = 1/2 x₁ = - 1/√2 x₂ = 1/√2 г) (x -1) (x+1) = 2(x^2 - 3) x² - 1 = 2x² - 6 x² = 5 x₁ = - √5 x₂ = √5
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