Ответы на вопрос:
Y'+sqrt(x)*y=sqrt(x)*y^2 y'+y√(x)=√(x)*y² y'= √(x)*y² - y√(x) y'= √(x)*(y² - y) dx*(y'/(y^2 - y)) = (√(x))*dx dx*(dy/dx/(y² - y)) = (√(x))dx dy/(y² - y) = (√(x))dx ʃdy/(y² - y) = ʃ√(x)dx ʃ√(x)dx = (2*³√x²)/3 + c1 ʃdy/(y² - y) = ʃdy/y(y - 1) = ln|(y - 1)/y|+c2 (2*³√x²)/3 + c1 = ln|(y - 1)/y|+c2 e^((2*³√x²)/3 + c1)-c2 = (y - 1)/y e^((2*³√x²)/3 + c1)-c2 = 1/y -1 1/y = e^((2*³√x²)/3 + c1)+1-c2 y= 1: (e^((2*³√x²)/3 + c1) - c2+1)
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