Ответы на вопрос:
У(x) = 1/√(x²+1) ; у'(x) = (1/√(x²+1) ) ' = ((x²+1)^(-1/2)) ' = (-1/2)*(x²+1)^(-3/2)*( x²+1)' =(-1/2)*(x²+1)^(-3/2)*2x = -x*(1/√(x²+1)³) = -x /√(x²+1)³. * * * или у'(x) = (1/√(x²+1) ) ' = ( (1)'*√(x²+1) - 1*(√(x²+1))' )/(√(x²+1) )² = (0 -(1/2)*(x²+1)^(-1/2)*(x²+1)' )/ (x²+1) = -x*(x²+1)^(-1/2) /(x²+1) = - x *(1/(x²+1)^(1/2) ) / (x²+1) = - x / (x²+1)√(x²+1) -x /√(x²+1)³ .
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