Ответы на вопрос:
A1+2d+a1+6d=24⇒2a1+8d=24⇒a1+4d=12⇒a1=12-4d (a1+2d)(a1+6d)=128(12-4d+2d)(12-4d+6d)=128 (12-2d)(12+2d)=128 144-4d²=128 4d²=144-128 4d²=16 d²=4 1)d1=-2 a1=12+8=20 a5=a1+4d=12 s8=(2a1+7d)*8/2 s8=(40-14)*4=26*4=104 2)d=2 a1=12-8=4 s8=(8+14)*4=22*4=88
| 5 - 2x| ≤ 7
5 - 2x ≤ 7; 5 - 2x ≥ 0
- ( 5 - 2x) ≤ 7; 5 - 2x < 0
x ≥ - 1; x ≤
x ≤ 6; x >
x∈ [ - 1; ]; x∈ (; 6]
x∈ [ - 1; 6]
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