Sin7alfa•cos 4alfa+sin 4alfa •cos 7alfa -3sin 11alfa=? sin2xcos3x-2sin5x+cos2xsin3x= cos2,5xcos1,5x+cosx+sin1,5xsin2,5x=? 2(cos4x•cos7x+sin2x)+2•sin4x•sin7x=?
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Ответы на вопрос:
1) sin7αcos4α +sin4αcos7α -3sin11α = sin11α - 3sin11α = -2sin11α 2) s in2xcos3x-2sin5x+cos2xsin3x=sin5x -2sin5x = -sin5x3)c os2,5xcos1,5x+cosx+sin1,5xsin2,5x= cosx +cosx = 2cosx4) 2(cos4x•cos7x+sin2x)+2•sin4x•sin7x==2cos4xcos7x +4sin2x +2sin4xsin7x = =2(cos4xcos7x +sin4xsin7x) +4sin2x = 2cos3x + 4sin4x
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