Find the mistakes and correct them. • is you doing anything? – • she play baseball every tuesday. – • are you wanting to play something with me for a change? – • they is boring. – • it’s not about who win or lose but how you play the game. –

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инна1903

Математика

4,5(26 оценок)

· is you doing anything? - are you doing anything? · she play baseball every tuesday. - she plays baseball every tuesday. · are you wanting to play something with me for a change? - do you want to play something with me for a change? · they is boring. – they are boring. · it’s not about who win or lose but how you play the game. - it’s not about who wins or loses but how you play the game

fuzzy77

Математика

4,7(42 оценок)

ответ:5

Пошаговое решение

1) \\ \sqrt{7 + 4 \sqrt{3} } + \sqrt{7 - 4 \sqrt{3} } = \sqrt{4 + 2 \times 2 \sqrt{3} + 3 } } + \sqrt{4 - 2 \times 2 \sqrt{3} + 3 }

Под корнем получаем полный квадрат, свернем его:

\sqrt{(2 + \sqrt{3}) {}^{2} } + \sqrt{(2 - \sqrt{3} ) {}^{2} } = |2 + \sqrt{3} | + |2 - \sqrt{3} |

Первый модуль раскрыли с плюсом, т.к. 2 + sqrt(3) > 0, второй модуль раскрыли так же с плюсом, т.к. 2 > sqrt(3)

|2 + \sqrt{3} | + |2 - \sqrt{3} | = 2 + \sqrt{3} + 2 - \sqrt{3} = 4

ответ: 4.

2) \\ \frac{ \sqrt{3} + \frac{}{} \sqrt{2} }{ \sqrt{3} - \sqrt{2} } - 2 \sqrt{6} = \frac{( \sqrt{3} + \sqrt{2} ) {}^{2} }{( \sqrt{3} - \sqrt{2})( \sqrt{3} + \sqrt{2} )} - 2 \sqrt{6} = \frac{ 3+ 2 \sqrt{6} + 2 }{( \sqrt{3} ) {}^{2} - ( \sqrt{2} ) {}^{2} } - 2 \sqrt{6} = \frac{5 + 2 \sqrt{6} }{3 - 2} - 2 \sqrt{6} = \frac{5 + 2 \sqrt{6} }{1} - 2 \sqrt{6} = 5 + 2 \sqrt{6} - 2 \sqrt{6} = 5

ответ: 5