I2x + 14i = 6 i9x-18i = 27 i8x +12i = 20 i15 x - 10i = 5 i9x + 15i = 6 i8x - 6i = 14' iixi - 3i = 0 i5- ixii = 0 iixi + 3i = 0 i7 - ixii=0
288
482
Ответы на вопрос:
I2x + 14i = 6 2х=-14+6 2х=-8 х=-8/2 х=-4 i9x-18i = 27 9х=27+18 9х=45 х=45/9 х= 5 i8x +12i = 20 8х=20-128х=8х=8/8х=1 i15 x - 10i = 5 15х=10+5 х=15/15 х=1 i9x + 15i = 6 9х=6-15 9х=-9 х=-9/9 х=-1 i8x - 6i = 14 8х=14+6 8х=20 х=20/8 х=2.5 iixi - 3i = 0 х=3 i5- ixii = 0 х= 5 iixi + 3i = 0 х=-3 i7 - ixii=0 х=7
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