Ответы на вопрос:
F(x) = arctg(x) x1 = 0.95 x0 = 1 f(x1) = f(0.95) = arctg(1 - 0.05) = arctg(x0 + dx) dx = -0.05 f(x1)≈ f(x0) + df df = (df/dx)*dx df/dx = 1/(1 + x²) | df/dx| = 1/(1 + x0²) = 1/2 |x0 df = (df/dx)*dx = (1/2)*(-0.05) = -0.025 f(x1) ≈ f(x0) + df = arctg(1) + (-0.025) = π/4 - 0.025 ≈ 0.760 более точное значение artcg(0.95) ≈ 0.75976275487577082892296119539998
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