Ответы на вопрос:
(x + 1)^8 = 256 (x + 1)^8 = 2^8 (x + 1)^8 - 2^8 = 0 [(x + 1)^4]^2 - (2^4)^2 = 0 [(x + 1)^4 + 2^4] * [(x + 1)^4 - 2^4] = 0 [(x + 1)^4 + 2^4] > 0 при любом значении х => [(x + 1)^4 - 2^4] = 0 [(x + 1)^2 + 2^2] * [(x + 1)^2 - 2^2] = 0 [(x + 1)^2 + 2^2] > 0 при любом значении х => [(x + 1)^2 - 2^2] = 0 [(x + 1) + 2] * [(x + 1 - 2] = 0 (x + 3) * (x - 1) = 0 x1 = - 3 x2 = 1
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