Ответы на вопрос:
Log₄x=log_(₂²) x=(1: 2)*log₂x=(1/2)*log₂x (7/2)*log₂x+(1/2)*log₂x=4 одз: x> 0 (7/2+1/2)*log₂x=4 4*log₂x=4 log₂x=1 x=2¹ x=2
1) 27*2^x-8*3^x=0 /3^x 27*(2/3)^x - 8 = 0 (2/3)^x = 8/27 (2/3)^x = (2/3)^3 x = 3 ответ: х = 3 2) 2^(x+1) - 2^(x-1)=3^(2-x) 2*(2^x) - (1/2)*(2^x) = 9/(3^x) (2^x) *(2 - 1/2) = 9/(3^x) (2^x)*(3/2) = 9/(3/2) (6^x) = 6^1 x = 1 ответ: х = 1 3) 9*(4^x) - 13*(6^x) + 4*(9^x) = 0 9*(2^2x) - 13*(2^x)*(3^x) + 4*(3^2x) = 0 /(3^2x) 9*(2/3)^2x - 13*(2/3)^x + 4 = 0 (2/3)^x = t 9t^2 - 13t + 4 = 0 d = 169 - 4*9*4 = 25 t1 = (13 - 5)/18 t1 = 4/9 t2 = (13 + 5)/18 t2 = 1 1) (2/3)^x = 4/9 (2/3)^x = (2/3)^2 x1 = 2 2) (2/3)^x = 1 (2/3)^x = (2/3)^0 x2 = 0 ответ: x1 = 2; x2 = 1
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