Ответы на вопрос:
Log₄8-log₉3+2*log(√5)125=log₄(2*4)-0,5*log₃3+4*log₅5³= =log₄2+log₄4-0,5+4*3*log₅5=0,5*log₂2+1-0,5+12=0,5+0,5+12=13. (1/2)log₂(1/16)+log₈16-2*log₆∛6+log(2*√2)√2= =log₂√(1/2⁴)+log(2³)2⁴-(2/3)log₆6+log(√2³)√2= =log₂(1/2)+4/3*log₂2-2/3+(1/3)log(√2)√2=log₂2⁻¹+4/3-2/3+1/3= =-log₂2+1=-1+1=0.
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