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Всплаве золото и серебро находится в отношении 2: 3 . найдите массу серебра если его в сплаве на 6 г больше , чем золота

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2х- золото, 3х - серебро 2х+6=3х 1х=6 золото = 2*6 =12 серебро = 3*6 =18

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