Ответы на вопрос:
2х*5х^2у - 4х^3у + х*у*у-4у *х*у=10x^3-4x^3-3y^2x=6x^3y-3y^2x=3xy(2x^2-y) х*у*у-4у *х*у=y^2x-4y^2x=-3y^2 x
34: 4 =8(қалдық 2) 19: 2=9(қ 1) 82: 8=10(қ 2) 15: 6. =2(қ 3) 27: 4. =6(қ 32) 29: 6=4(қ 5) 68: 8. =8(қ 4) 75: 9. =8(қ 3) 2: 7 бөлінбейді
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