Ответы на вопрос:
Y-x=1⇒y=x+1 x³-4xy+5y=-1 x³-4x²-4x+5x+5+1=0 x³-4x²+x+6=0 x²(x+1)-5x(x+1)+6(x+1)=0 (x+1)(x²-5x+6)=0 x+1=0⇒x1=-1⇒y1=-1+1=0 x²-5x+6=0 x2+x3=5 u x2+x3=6 x2=2⇒y2=2+1=3 x3=3⇒y3=3+1=4 (-1; 0); (2; 3); (3; 4)
Решение x² + 2px + 1 = 0 d = 4p² - 4*1*1 = 4(p² - 1) x₁ = (- 2p - 2√(p² - 1)) /2 x₁ = - p - √(p² - 1) x₂ = (- 2p + 2√(p² - 1)) /2 x₂ = - p + √(p² - 1) x₁ : x₂ = 9 [- p - √(p² - 1)] : [- p + √(p² - 1)] = 9 - p - √(p² - 1) = 9 * [- p + √(p² - 1)] - p - √(p² - 1) = - 9p + 9√(p² - 1) - 9p + 9√(p² - 1) + p + √(p² - 1) = 0 10√(p² - 1) = 8p [10√(p² - 1)]² = (8p)² 100(p² - 1) = 64p² 100p² - 100 - 64p² = 0 36p² = 100 p² = 100/36 p₁ = - 10/6 = - 5/3 = - 1 (2/3) p₂ = 10/6 = 1 (2/3)
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