Ответы на вопрос:
{3}+2\sqrt{2})^{2}=(\sqrt{3})^{2}+2*\sqrt{3}*2\sqrt{2}+(2\sqrt{2})^{2}-4\sqrt{6} =3+4\sqrt{6}+8-4\sqrt{6}=3+8=11[/tex]
{5}-\sqrt{15})^{2}+\sqrt{300}=(\sqrt{5})^{2}-2*\sqrt{5}*\sqrt{15}+(\sqrt{15})^{2}+\sqrt{300}=5-2\sqrt{75}+15+\sqrt{300}=20-\sqrt{4*75}+\sqrt{300}=20-\sqrt{300}+\sqrt{300}=20[/tex]
{3}-\sqrt{5})^{2}+\sqrt{60}=(\sqrt{3})^{2}-2*\sqrt{3}*\sqrt{5}+(\sqrt{5})^{2}+\sqrt{60}=3-2\sqrt{15}+5+\sqrt{60}=8-\sqrt{4*15}+\sqrt{60}=8-\sqrt{60}+\sqrt{60}=8[/tex]
{3}+1)^{2}(4-2\sqrt{3})={3})^{2}+2*\sqrt{3}*1+1^{2}]*(4-2\sqrt{3})=(3+2\sqrt{3}+1)(4-2\sqrt{3})=(4+2\sqrt{3})(4-2\sqrt{3})=4^{2}-(2\sqrt{3})^{2}=16-12=4[/tex]
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