Ответы на вопрос:
X^2 - 3y^2 = 12 x + y = 6 x^2 - 3y^2 = 12 y = 6 - x x^2 - 3 (6 - x)^2 - 12 = 0 x^2 - 3 (x^2 - 12x + 36) - 12 = 0 x^2 - 3x^2 + 36x - 108 - 12 = 0 - 2x^2 + 36x - 120 = 0 // : (-2) x^2 - 18x + 60 = 0 d = 324 - 240 = 84 x₁ = ( 18 + 2√21)/2 = 9 + √21 x₂ = ( 18 - 2√21)/2 = 9 - √21 x₁ = 9 + √21 y₁ = 6 - (9 + √21) = - 3 - √21 x₂ = 9 - √21 y₂ = 6 - (9 - √21) = - 3 + √21
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