Ответы на вопрос:
2sin x - 4cos x - sin x/cos x - cos x/sin x + 2cos^2 x/sin x + 2 = 0 умножаем все на sin x*cos x 2sin^2 x*cos x - 4cos^2 x*sin x - sin^2 x - cos^2 x + 2cos^3 x + 2sin x*cos x = 0 2sin x*cos x*(sin x - cos x) - 2sin x*cos^2 x + 2cos^3 x = = sin^2 x + cos^2 x - 2sin x*cos x 2sin x*cos x*(sin x - cos x) + 2cos^2 x*(cos x - sin x) = (sin x - cos x)^2 (sin x - cos x)*(2sin x*cos x - 2cos^2 x) = (sin x - cos x)^2 2cos x* (sin x - cos x)* (sin x - cos x) = (sin x - cos x)^2 (sin x - cos x)^2*(2cos x - 1) = 0 1) sin x = cos x tg x = 1; x1 = pi/4 + pi*k 2) cos x = 1/2 x2 = +-pi/3 + 2pi*k
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