Ответы на вопрос:
B1(1+q+q^2+q^3)=8 b1(q^4+q^5+q^6+q^7)=4 (q^3+q^2+q+1)/(q^4(q^3+q^2+q+1))=2 q^4=1/2 q=(1/2)^(1/4) b1=8(q-1)/(q^4-1) = 16*(1-(1/2)^(1/4)) s12=b1*(q^12-1)/(q-1) = 16*(1-(1/2)^(1/4))*(1/8-1)/((1/2)^(1/4)-1) = 14
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