Ответы на вопрос:
Решение 3x^{4} - 13x^{2}+4=0x² = t, t ≥ 0 3t² - 13t + 4 = 0 d = 169 - 4*3*4 = 121 t1 = (13 - 11)/6 t1 = 1/3 t2 = (13 + 11)/6 t2 = 4 1) x² = 1/3 x1 = - √3/3 x2 = √3/3 2) x² = 4 x3 = - 2 x4 = 2
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