Ответы на вопрос:
1)x^2/3 - 3 = 0 x^2/3 = 3 х^2 = 9 x1=3 x2= - 3 2)b1=3*2-1 = 6-1 = 5 b2 = 3*2^2 - 1 = 12-1 = 11 q=b2/b1 = 11/5 +1)/2a)/((a^2-1)/4a^2)) = (a+1)*4a^2/2a*(a^2-1) = (a+1)*2a/(a-1)(a+1) = 2a/a-1
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