Найти множество значений функции 1)у =1-2sin^2х 2)y=2cos^2x-1 3)y=3-2sin^2x 4)y=2cos^2x+5
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354
Ответы на вопрос:
1< = sinx < = 1 0 < = (sinx)^2 < = 1 0 < = 2(sinx)^2 < = 2 0 > = -2(sinx)^2 > = -2 -2 < = -2(sinx)^2 < = 0 1-2 < = 1-2(sinx)^2 < = 1 -1 < = 1-2(sinx)^2 < = 1 -1 < = cosx < = 1 0 < = (cosx)^2 < = 1 0 < = 2(cosx)^2 < = 2 -1 < = 2(cosx)^2-1 < = 1 -2 < = -2(sinx)^2 < = 0 1 < = 3-2(sinx)^2 < = 3 0 < = 2(cosx)^2 < = 2 5 < = 2(cosx)^2+5 < = 7
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