Ответы на вопрос:
Cosx+√3sinx=-2sin2x 2(√3/2sinx-1/2cosx)=2sin2x sin(x-π/6)=sin2x sin2x-sin(x-π/6)=0 2sin(x/2+π/12)cos(3x/2-π/12)=0 sin(x/2+π/12)=0⇒x/2+π/12=πn⇒x/2=-π/12+πn⇒x=-π/6+2ππn,n∈z cos(3x/2-π/12)=0⇒3x/2-π/12=π/2+πk⇒3x/2=7π/12+πk⇒x=7π/18+2πk/3,k∈z
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