Найти кол-во и сумму отрицательных значений y. y=a(1+l)/l . где a не равно нулю , а l пренадлежит [-2.5 : 2.5] c шагом 0.52
Ответы на вопрос:
ответ:
type man = record
name: string;
surname: string;
date: record
day: integer;
month: integer;
year: integer;
end;
end;
var people: array [1..100] of man;
i,n,_year: integer;
_name: string;
begin
write('enter number of man: ');
readln(n);
for i : = 1 to n do
with people[i] do
begin
writeln('man[',i,']: ');
write('enter name: ');
readln(name);
write('enter surname: ');
readln(surname);
write('enter birthday day/month/year: ');
readln(date.day, date.month, date.year);
writeln;
end;
write('enter year: ');
readln(_year);
for i : = 1 to n do
with people[i] do
if (date.year = _year) then
writeln('name: ',name,' surname: ',surname);
writeln;
write('enter name: ');
readln(_name);
for i : = 1 to n do
with people[i] do
if (name = _name) then
begin
write(surname,' ',name);
writeln(' ',date.day,'.',date.month,'.',date.year);
end;
readln;
end.
объяснение:
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