Ответы на вопрос:
101(x) = 1*x^2+0*x^1+1 101(x+1) = (x+1)^2+1 x^2+1 + 13 = (x+1)^2+1 x^2 + 14 = (x+1)^2+1 (x+1)^2 -13- x^2 = 0 x^2 + 2x + 1 - 13 - x^2 =0 2x = 12 x = 6 47 + 13 = 50
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