Ответы на вопрос:
Cosα)^4 +(sinα)^4 если sin2α = 2/3 . (cosα)^4 +(sinα)^4 =(cos²α+sin²α)² - 2sin²α*cos²α = 1 -2*(sinα*cosα)² =1 -2*(1/2*sin2α)² = =1 -1/2*sin²2α = 1-1/2*(2/3)² =1 - 2/9 = 7/9.
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