Ответы на вопрос:
3sin²(x/2)+sin(x/2)*cos(x/2)-2sin²(x/2)-2cos²(x/2)=0 sin²(x/2)+sin(x/2)cos(x/2)-2cos²(x/2)=0 (/cos²x/2≠0 (sin(x/2)/cos(x/2))²+sin(x/2)/cos(x/2)-2=0 tg²x/2+tgx/2-2=0 tgx/2=t t²+t-2=0 t=1 t=-2 tgx/2=1 tgx/2=-2 x/2=π/4+πn x/2=-arctg2+πn x=π/2+2πn x=-2arctg2+2πn
4x=-6y | : 2 7y-2x=20 2x=-3y 7y-2x=20 2x=-3y 7y+3y=20 2x=-3y 10y=20 y=2 x=-3
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