Ответы на вопрос:
Var mas: array[1..1000] of integer; n, i, c: integer; begin readln(n); for i: =1 to n do readln(mas[i]); for i: =1 to (n div 2) do begin c: =mas[i]; mas[i]: =mas[n-i+1]; mas[n-i+1]: =c; end; for i: =1 to n do write(mas[i],' '); end.
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