Ответы на вопрос:
пошаговое объяснение:
{gathered}3\frac{1}{6}-\left( {x+1\frac{1}{{12}}} \right)=\frac{1}{4} \hfill \\x+1\frac{1}{{12}}=3\frac{1}{6}-\frac{1}{4} \hfill \\x+1\frac{1}{{12}}=3\frac{2}{{12}}-\frac{3}{{12}} \hfill \\x+1\frac{1}{{12}}=2\frac{{14}}{{12}}-\frac{3}{{12}} \hfill \\ \end{gathered} /tex]
{gathered}x+1\frac{1}{{12}}=2\frac{{11}}{{12}} \hfill \\x=2\frac{{11}}{{12}}-1\frac{1}{{12}} \hfill \\x=1\frac{{10}}{{12}}=\boxed{1\frac{5}{6}} \hfill \\ \end{gathered}/tex]
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