Find the molar mass of aluminum sulfate . Indicate the relative molecular weight of the substance.
220
308
Ответы на вопрос:
given:
АІ2(SО4)3
find:
М[АІ2(SО4)3] -?
Мr[АІ2(SО4)3] -?
Solution:
М[АІ2(SО4)3] = А(АІ) • n(АІ) + А(S) • n(S) + А(О) • n(О)
М[АІ2(SО4)3] = 27 • 2 + (32 + 16 • 4) • 2 = 54 + 96 • 3 =
= 54 + 288 = 342 g/mol
Мr[АІ2(SО4)3] = Аr(АІ) • n(АІ) + Аr(S) • n(S) + Аr(О) • n(О)
Мr[АІ2(SО4)3] = 27 • 2 + (32 + 16 • 4) • 2 = 54 + 96 • 3 =
= 54 + 288 = 342 .
Answer: М[АІ2(SО4)3] = 342 g/mol; Мr[АІ2(SО4)3] = 342.
АІ2(SО4)3
find:
М[АІ2(SО4)3] -?
Мr[АІ2(SО4)3] -?
Solution:
М[АІ2(SО4)3] = А(АІ) • n(АІ) + А(S) • n(S) + А(О) • n(О)
М[АІ2(SО4)3] = 27 • 2 + (32 + 16 • 4) • 2 = 54 + 96 • 3 =
= 54 + 288 = 342 g/mol
Мr[АІ2(SО4)3] = Аr(АІ) • n(АІ) + Аr(S) • n(S) + Аr(О) • n(О)
Мr[АІ2(SО4)3] = 27 • 2 + (32 + 16 • 4) • 2 = 54 + 96 • 3 =
= 54 + 288 = 342 .
Answer: М[АІ2(SО4)3] = 342 g/mol; Мr[АІ2(SО4)3] = 342.
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